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  • SSC CGL Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Quadratic Equations for SSC CGL Exam student. This free online Quantitative Aptitude study material for SSC CGL Exam will help students in learning and doing practice on Quadratic Equations topic of SSC CGL Exam Quantitative Aptitude. The study material on Quadratic Equations, help SSC CGL Exam Quantitative Aptitude students to learn every aspect of Quadratic Equations and prepare themselves for exams by doing online test exercise for Quadratic Equations, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SSC CGL Exam Quantitative Aptitude Quadratic Equations exercise prepared by the highly professionals team. Students can understand Quadratic Equations concept easily and consolidate their learning by doing practice test on Quadratic Equations regularly till they excel in Quantitative Aptitude Quadratic Equations.


Quadratic Equations
If a=√x+2+√x-2/√x+2√x-2 then the value of (a2-ax)is

a) 1
b) 2
c) -1
d) 0



Answer
Correct Answer Is : -1
Solution Is :
The HCF of X8 - 1 and X4 + 2X3 - 2X - 1

a) X2+1
b) X+1
c) X2-1
d) X-1



Answer
Solution
Correct Answer Is : X2-1
Solution Is :
The least number which when divided by 6,9,12,15,18 leaves the same remainder 2 in each case is:

a) 178
b) 182
c) 176
d) 180



Answer
Solution
Correct Answer Is : 182
Solution Is :
If X=X24 + 1/X12 = 7then the X72 + 1/X36 value of

a) 432
b) 433
c) 343
d) 322



Answer
Solution
Correct Answer Is : 322
Solution Is :
If 5x + 9y = 5 and 125x + 729y = 120 then the value of the product of x and y is

a) 135
b) 1/135
c) 1/9
d) 45



Answer
Solution
Correct Answer Is : 1/135
Solution Is : 5x +9y = 5 ...(i)
125x3+ 729y3=120 ...(ii)
Now cube both sides of equation (i), we get
⇒ (5x + 9y)3= (5)3
⇒125x3 + 729y3+135xy(5x +9y)=125
⇒ 125x3 + 729y3 +135xy *5 =125
Now, put the value of equation (i)
120 + 135 xy × 5 = 125
⇒ 135 × 5xy = 125 - 120
⇒135 × 5xy = 5 ⇒
xy=(5/(135*5))=1/135
If p = 99 then, the value of p(p2 + 3p + 3) is :

a) 999999
b) 988899
c) 989898
d) 998889



Answer
Solution
Correct Answer Is : 999999
Solution Is : Given P = 99
then P(P2 + 3P + 3)
= P((P + 1)2+ P + 2)
= 99 ((99 + 1)2 + 101)
= 99 × (10000 + 101)
= 999999
The least number which when divided by 48, 64.90, 120 will leave the remainders 38, 54, 80, 110 respectively, is

a) 2870
b) 2860
c) 2890
d) 2880



Answer
Solution
Correct Answer Is : 2870
Solution Is :

a)
b)
c)
d)



Answer
Solution
Correct Answer Is :
Solution Is :

a) 535
b) 1030
c) 790
d) 970



Answer
Solution
Correct Answer Is : 970
Solution Is :

a) 19-Feb
b) 17-Feb
c) 18-Mar
d) 15-Feb



Answer
Solution
Correct Answer Is : 19-Feb
Solution Is :

Preparation for Exams

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