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  • UIIC ASSISTANT RECRUITMENT Numerical Ability Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Numerical Ability Problems on Ages for UIIC ASSISTANT RECRUITMENT student. This free online Numerical Ability study material for UIIC ASSISTANT RECRUITMENT will help students in learning and doing practice on Problems on Ages topic of UIIC ASSISTANT RECRUITMENT Numerical Ability. The study material on Problems on Ages, help UIIC ASSISTANT RECRUITMENT Numerical Ability students to learn every aspect of Problems on Ages and prepare themselves for exams by doing online test exercise for Problems on Ages, as their study progresses in class. Kidsfront provide unique pattern of learning Numerical Ability with free online comprehensive study material and loads of UIIC ASSISTANT RECRUITMENT Numerical Ability Problems on Ages exercise prepared by the highly professionals team. Students can understand Problems on Ages concept easily and consolidate their learning by doing practice test on Problems on Ages regularly till they excel in Numerical Ability Problems on Ages.


Problems on Ages
Theratio of age of two boys is 5:6 .After 2 yr the ratio will be 7:8 .The ratio of their ages after 12 yr will be

a) 15/16
b) 17/18
c) 11/12
d) 22/24



Answer
Solution
Correct Answer Is : 17/18
Solution Is : Let the ages of two boys be 5x and 6x ,respectively Acording to the question
5x+2/6x+2 =7/8
40 x + 16 = 42 x + 14
2x =2
x= 1Now ratio of their ages after 12 yr =5x +12/6x+12
=17.18
Nikhil is 8 yr younger than his brother Rohan. How old will Rohan be when he is twice he is twice as old as Nikhil?

a) 4
b) 6
c) 8
d) 16



Answer
Solution
Correct Answer Is : 16
Solution Is : Let age of Nikhil = x yr
and age of Rohan = (x + 8) yr
According to the question, x + 8 = 2x -->x = 8
The age of Rohan = 8 + 8 = 16 yr
Lakshmi is elder than Meenu. Leela is elder than Meenu but younger than Lakshmi. Latha is younger than Both Meenu and Hari but Hari is younger than Meenu. Who is the youngest?

a) Lakshmi
b) Meenu
c) Leela
d) Latha



Answer
Solution
Correct Answer Is : Latha
Solution Is : According to the question, Lakshmi > Meenu Lakshmi > Leela > Meenu Meenu > Hari > Latha --> Lakshmi > Leela > Meenu > Hari > Latha
Rajan is younger than his father by 20 years . 5 years ago his father was 3 times elder than him . Fin the present age of his father ?

a) 25
b) 30
c) 35
d) 36



Answer
Solution
Correct Answer Is : 35
Solution Is : The present age of his father is 35 years c
Theaverage age of A and B is 20 yr . If A is to be replaced by C , the average would be 19 yr . The average age of C and A is 21 yr . The ages of A , B and C in order ( in years ) are

a) 22,18,20
b) 22,20,18
c) 18,22,20
d) 18,20,22



Answer
Solution
Correct Answer Is : 22,18,20
Solution Is :
The area of an equilateral triangle is 48 sq m . The length of side is,

a) √8 x 4 cm
b) 4√3 cm
c) 8 cm
d) 16cm



Answer
Solution
Correct Answer Is : 8 cm
Solution Is : The correct option is answer C ie 8 cm
My grandfather was 9 times older than 16 years ago. He will be 3 times of my age from now. 8 years ago, the ratio of my age to that of my grandfather was

a) 3:8
b) 2:5
c) 1:2
d) 1:5



Answer
Solution
Correct Answer Is : 1:5
Solution Is :
Mani is double the age of Prabhu. Ramona is half the age of Prabhu. If Mani is sixty , find out the age of Ramona.

a) 20
b) 15
c) 10
d) 24



Answer
Solution
Correct Answer Is : 15
Solution Is : Let age of prabhu be x yr. Then , according to question
Prabhu : Mani : Ramona
xyr : 2xyr : xyr/2
2x = 60
x = 30
age of ramona= 30/2 = 15 yr
3 yr ago the average age of a family of 5 members was 17 yr. A baby having been born, the average age of the family is the same today. The present age of the baby is ,

a) 1 yr
b) 1 1/2 yr
c) 2 yr
d) 3 yr



Answer
Solution
Correct Answer Is : 2 yr
Solution Is : Let present age of baby be x ,
total age of family members
= 17 * 5 + 3 * 5
= 85 + 15 = 100 yr
given, ( 100 + x ) / 6 = 17
100 + x = 102
x = 102 -100
x = 2 yr
3 year ago the average age of a family of 5 members was 17 yr .A bay having been born, the average age of the family remains the same today .the age of the baby today

a) 3 yr
b) 2 yr
c) 1 yr
d) 1.5 yr



Answer
Solution
Correct Answer Is : 2 yr
Solution Is : Total precent age of five members
=17*5+3*5
=85+15
=100yr
let x years be the precent age of baby
according to question
100+x=102
x=102-100=2yr
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