Online Test      LOGIN      SIGN UP
Forgot your password?
  • SSC CHSL Exam SSC CHSL Quantative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of SSC CHSL Quantative Aptitude Geometry for SSC CHSL Exam student. This free online SSC CHSL Quantative Aptitude study material for SSC CHSL Exam will help students in learning and doing practice on Geometry topic of SSC CHSL Exam SSC CHSL Quantative Aptitude. The study material on Geometry, help SSC CHSL Exam SSC CHSL Quantative Aptitude students to learn every aspect of Geometry and prepare themselves for exams by doing online test exercise for Geometry, as their study progresses in class. Kidsfront provide unique pattern of learning SSC CHSL Quantative Aptitude with free online comprehensive study material and loads of SSC CHSL Exam SSC CHSL Quantative Aptitude Geometry exercise prepared by the highly professionals team. Students can understand Geometry concept easily and consolidate their learning by doing practice test on Geometry regularly till they excel in SSC CHSL Quantative Aptitude Geometry.


Geometry
In ?ABC , ?A = 30°,?B = 60°.Find ?c in circular measure

a) π°/6
b) π°/2
c) 2π°/3
d) 3π°/4



Answer
Solution
Correct Answer Is : π°/2
Solution Is :

An equation whose graph passes through the origin,out of the given equations 2X + 3Y=2 , 2X-3Y=3 , -2X+3Y=5 and 2X+3Y=0 is

a) 2X+3Y=2
b) 2X-3Y=3
c) FALSE
d) 2X+3Y=0



Answer
Solution
Correct Answer Is : 2X+3Y=0
Solution Is : Any equation through origin must satisfy the point (0,0) only equation 2x+3y = 0 satisfies the above point .
A unique circle can always be drawn through x number of given non-collinear points,then x must be

a) 1
b) 2
c) 3
d) 4



Answer
Solution
Correct Answer Is : 3
Solution Is : A unique circle can always be drawn from 3 non-collinear points.
If Triangle ABC is similar to Triangle DEF ,such that Angle A= 47° Angle E = 63°,then Angle C is equal to

a) 37°
b) 40°
c) 70°
d) 65°



Answer
Solution
Correct Answer Is : 70°
Solution Is :

Abcd is aquadrilateral inscribed in a circle with centre O.If Angle COD =120° and Angle BAC =30°, then Angle BCD is

a) 60°
b) 75°
c) 90°
d) 120°



Answer
Solution
Correct Answer Is : 90°
Solution Is :
ABCD is a trapezium whose side AD is parallel to BC,Diagonals AC and BD Intersect at o.if AO=3,CO=x-3,Bo=3x-19 and DO=x-5,the value (s) of x will be

a) 8,9
b) 7,6
c) 12,6
d) 7,10



Answer
Solution
Correct Answer Is : 8,9
Solution Is :
There are two temples ,one on each bank of a river just opposite to each other .one temple is 54 m high.From the top of this temple ,the angles of depression of the top and the foot of the other temple are 300 and 60 0 ,respectively .The height of the temple is

a) 18√3 m
b) 18m
c) 36m
d) 36√3 m



Answer
Solution
Correct Answer Is : 36m
Solution Is :

Thelength of the shadow of a vertical tower on level ground increases by 10 m when the altitude of the sun changes from 45o to 30o Then the height of the tower is

a) 10(√3+1)m
b) 5(√3+1)m
c) 10√3m
d) 5√3m



Answer
Solution
Correct Answer Is : 5(√3+1)m
Solution Is :
If 5 tanθ=4,then 5sin θ-3cos θ/5 sinθ+ 2cosθ is equal to

a) 1/4
b) 1/6
c) 1/3
d) 2/3



Answer
Solution
Correct Answer Is : 1/6
Solution Is :
If x sinθ - y sinθ =√(x2+y2) and cos 2 θ/a2 ++ sin 2 θ/b2 =1 /x2 + y2 then the correct relation is

a) X2/a2 +y2/b2 = 1
b) X2/b2 +y2/a2 =1
c) X2/a2 - y2/ b2
d) X2/b2 -y2/a2 =1



Answer
Solution
Correct Answer Is : X2/b2 +y2/a2 =1
Solution Is :
PREVIOUS

Preparation for Exams

script type="text/javascript">