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  • SBI SO Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Pipes and Cisterns for SBI SO Exam student. This free online Quantitative Aptitude study material for SBI SO Exam will help students in learning and doing practice on Pipes and Cisterns topic of SBI SO Exam Quantitative Aptitude . The study material on Pipes and Cisterns, help SBI SO Exam Quantitative Aptitude students to learn every aspect of Pipes and Cisterns and prepare themselves for exams by doing online test exercise for Pipes and Cisterns, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SBI SO Exam Quantitative Aptitude Pipes and Cisterns exercise prepared by the highly professionals team. Students can understand Pipes and Cisterns concept easily and consolidate their learning by doing practice test on Pipes and Cisterns regularly till they excel in Quantitative Aptitude Pipes and Cisterns.


Pipes and Cisterns
Pipe A alone can fill a tank in 8 hours. Pipe B alone can fill it in 6 hours. If both the pipes are opened and after 2 hours pipe A is closed, then the other pipe will fill the tank in

a) 6 hours
b) 3.5 hours
c) 4 hours
d) 2.5 hours



Answer
Solution
Correct Answer Is : 2.5 hours
Solution Is :
Water is flowing at the rate of 5 km/h through a pipe of diameter 14 cm into a rectangular tank which is 50 m long, 44m wide. The time taken, in hours, for the rise in the level of water in the tank to be 7 cm is

a) 2
b) 1.5
c) 3
d) 2.5



Answer
Solution
Correct Answer Is : 2
Solution Is : diameter of pipe is 14cm or 14/100 m then radius is 7/100m water is flowing at rate of 5km/h or 5000m/h then water flow in 1h= (22*5000*7*7)/(7**100100) = 77 cube m rectangular tank is 50m long and 44m wide and height will be 7cm or 7/100m volume of tank= (50*44*7)/100 =154 cube m77cube m water take time to flow= 60minute 1 cube m water take time to flow= 60/77 minute 154 cube m water take time to flow= (60*154)/77 minute =120minuteor =2hour.
Water flows into a tank which is 200mlong and 150mwide, through a pipe of cross-section 0.3m × 0.2m at 20 km/hour. Then the time (in hour) for the water level in the tank to each 8cm is

a) 50
b) 120
c) 150
d) 200



Answer
Solution
Correct Answer Is : 200
Solution Is : Water supplied by pipe in 1 hour =(0.3 × 0.2 ×20 × 1000) cubicmeter = 1200 cubic metre Therefore Total time =( Volume of water to be filled in the tank )/1200 =(200 *150 * 8)/1200 = 200 hours
Two equal vessels are filled with the mixture ofwater and milk in the ratio of 3:4 and 5:3 respectively. If the mixtures are poured into a third vessel, the ratio of water and milk in the third vessel will be

a) 15:12
b) 53:59
c) 20:9
d) 59:53



Answer
Solution
Correct Answer Is : 59:53
Solution Is : Let the capacity of each vessel = 1 litre.
In First Vessel, Water= 3 /7 litre :Milk= 4/7 litre.
In Second Vessel, Water= 5 /8 litre ; Milk= 3/8 litre. In 2 litres of mixture, Water : milk
Therefore water : milk = 59 : 53
Pipe A is an inlet pipe filling the tank at 800 l/hr. Pipe B empties the tank in 3 hours. The capacity of the tank is

a) 12000 l
b) 8000 l
c) 6000 l
d) 4000 l



Answer
Solution
Correct Answer Is : 12000 l
Solution Is : Pipe A is an inlet pipe filling the tank at 800 l/hr. Pipe B empties the tank in 3 hours. The capacity of the tank is 1200 l
Two pipes, P and Q can fill a cistern in 12 and 15 minutes respectively. If both are opened together and at the end of 3 minutes, the first is closed, how much longer will the cistern take to fill?

a) 5minutes
b)
c)
d)



Answer
Solution
Correct Answer Is :
Solution Is :
A pipe can fill a tank in x hours and another can empty it in y hours. They can together fill it in (y > x )

a) X-y
b) Y-x
c) Xy/x-y
d) Xy/y-x



Answer
Solution
Correct Answer Is : Xy/y-x
Solution Is : Work done by A in one hour =1/x
work done by B in one hour=1/y
Both A and B together work in one hour=(1/x)-(1/y) =(y-x)/xy.
Both A and B fill tank in xy/(y-x) hours.
A tap can empty a tank in 30 minutes. A second tap can empty it in 45 minutes. If both the taps operate simultaneously, how much time is needed to empty the tank ?

a) 18 minutes
b) 14 minutes
c) 15 minutes
d) 30 minutes



Answer
Solution
Correct Answer Is : 18 minutes
Solution Is : Work done by 1st tap in one minute =1/30
work done by 2nd tap in one minute =1/45
Both taps one minute work =(1/30)+(1/45)
=(45+30)/1350
=75/1350 =1/18.
Both tap will empty the tank in 18 minutes.
Water is flowing at the rate of 3 km/hr through a circular pipe of 20 cm internal diameter into a circular cistern of diameter 10m and depth 2m. In how much time will the cistern be filled ?

a) 1 hour
b) 1 hour 40 minutes
c) 1 hour 20 minutes
d) 2 hours 40 minutes



Answer
Solution
Correct Answer Is : 1 hour 40 minutes
Solution Is :
An empty pool being filled with water at a constant rate takes 8 hours to fill 3/5 th of its capacity. How much more time will it take to finish filling the pool ?

a) 4 hours 50 minutes
b) 5 hours 30 minutes
c) 5 hours 20 minutes
d) 4 hours 48 minutes



Answer
Solution
Correct Answer Is : 5 hours 20 minutes
Solution Is :
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