#### SBI PO Exam Quantitative Aptitude Study Material

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b) Y-x

c) Xy/x-y

d) Xy/y-x

work done by B in one hour=1/y

Both A and B together work in one hour=(1/x)-(1/y) =(y-x)/xy.

Both A and B fill tank in xy/(y-x) hours.

b) 14 minutes

c) 15 minutes

d) 30 minutes

work done by 2nd tap in one minute =1/45

Both taps one minute work =(1/30)+(1/45)

=(45+30)/1350

=75/1350 =1/18.

Both tap will empty the tank in 18 minutes.

b) 1 hour 40 minutes

c) 1 hour 20 minutes

d) 2 hours 40 minutes

b) 5 hours 30 minutes

c) 5 hours 20 minutes

d) 4 hours 48 minutes

b) 80 hours

c) 90 hours

d) 100 hours

Part filled with leak in 1 hour = 1/10

Work done by leak in 1 hour =1/9?1/10=1/90

We used subtraction as it is getting empty.

So total time to empty the cistern is 90 hours

b) 2 1/2 hours

c) 3 1/3 hours

d) 5 1/3 hours

b) 25 minutes

c) 30 minutes

d) 45 minutes

b) 17/3minutes

c) 45/7 minutes

d) 5/4 minutes

b) 12

c) 36

d) 24

Therefore,part of tank filled in 12 minutes=(12/15)=2/3 part

Remaning part=1-(2/3)=1/3 part

when pipe Cis opened,part of tank filled by all 3 pipes=(1/30)(1/45)-(1/36)=5/180=1/36.

therefore,Time taken in filling 1/3 part = (1/3)*36=12 minutes,

therefore,Total time=12+12 =24 minutes.

b) 3 1/2

c) 3 1/4

d) 4 2/3