Online Test      LOGIN      SIGN UP
Forgot your password?
  • SBI PO Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Number Series for SBI PO Exam student. This free online Quantitative Aptitude study material for SBI PO Exam will help students in learning and doing practice on Number Series topic of SBI PO Exam Quantitative Aptitude. The study material on Number Series, help SBI PO Exam Quantitative Aptitude students to learn every aspect of Number Series and prepare themselves for exams by doing online test exercise for Number Series, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SBI PO Exam Quantitative Aptitude Number Series exercise prepared by the highly professionals team. Students can understand Number Series concept easily and consolidate their learning by doing practice test on Number Series regularly till they excel in Quantitative Aptitude Number Series.


Number Series
A and B entered into a partnership investing Rs 16000 and Rs. 12000 respectively. After 3 months A withdrew Rs. 5000 while B invested Rs. 5000 more. After 3 more months C joins the business with a capital of Rs 21000. The share of B exceeds that of C, out of a total profit of Rs. 26400 after one year by

a) Rs. 2400
b) Rs. 1200
c) Rs. 3600
d) Rs. 4800



Answer
Solution
Correct Answer Is : Rs. 3600
Solution Is : Ratio of equivalent capitals of A,B and C for 1 month = (16000 * 3 + 11000 * 9) : ( 12000 *3 + 17000 *9): (21000 *6) = (48000 + 99000) : ( 36000 + 153000) : 126000 = 147000:189000 :126000 = 49: 63 : 42 = 7: 9 : 6 . Sum of ratios +7+9+6 =22. Therefore required difference =Rs.((9-6)/22) * 26400) = Rs. (3* 26400)/22 =Rs.3600.

a) 2:1
b) 3:2
c) 1:1
d) 3:1



Answer
Solution
Correct Answer Is : 3:1
Solution Is :
What must be added to each term of the ratio 2:5 so that it may equal to 5:6?

a) 12
b) 78
c) 65
d) 13



Answer
Solution
Correct Answer Is : 13
Solution Is : According to question (2+x)/(5+x) = 5/6
⇒ 12+6x = 25+5x ⇒x=25-12 =13
If 3/4 of a number is 7 more then 1/6 of the number, then 5/3 of the number is

a) 15
b) 18
c) 12
d) 20



Answer
Solution
Correct Answer Is : 20
Solution Is : Let the number be x.
⇒ (3/4)x=(1/6)x+7
⇒ (3/4)x-(1/6)x =7
⇒ (9x-2x)/12 =7
⇒(7/12)x =7 . Therefore x=12.
Now 5/3 of x =(5/3)*12 =20
If A and B are in the ratio 4:5 and the difference of their squares is 81, what is the value of A?

a) 36
b) 15
c) 45
d) 12



Answer
Solution
Correct Answer Is : 12
Solution Is :
Ratio Now , B2-A2=81 A/B =4/5
⇒ B/A =5/4.
Squaring both sides , we get
⇒B2/A2 =25/16.
Both sides subtract 1
=⇒(B2-A2)/A2 =(25-16)/16 =9/16
⇒81/A2 =9/16
⇒ A2 =16*9 ⇒ A=12
If two numbers are in the ratio 2 : 3 and the ratio becomes 3 : 4 when 8 is added to both the numbers is

a) 10
b) 80
c) 40
d) 100



Answer
Solution
Correct Answer Is : 40
Solution Is :
The ratio of the first and second class fares between two stations is 4 : 1 and that of the number of passengers travelling by the first and second class is 1 : 40. If Rs. 11000 is collected as total fare, then the amount collected from the first class passengers is

a) Rs. 1375
b) Rs. 3150
c) Rs. 800
d) Rs. 1000



Answer
Solution
Correct Answer Is : Rs. 1000
Solution Is : Let number of passengers in first class be x and number of passengers in second class be 40x. Then, total amount of first class =4x and total amount of second class =40x Ratio of the amounts collected from the first class and the second class passengers = 4 : 40 Amount collected from the first class passengers
The ratio of two numbers is 3 : 4 and their LCM is 180. The second number is

a) 30
b) 60
c) 45
d) 90



Answer
Solution
Correct Answer Is : 60
Solution Is : Numbers = 3x and 4x
Their LCM = 3*4*x =12x.
Therefore 12x=180 =⇒
x=180/12 =15.
Second number=4x = 4*15=60.
Which of the following represents a correct proportion?

a) 12:9 = 16:12
b) 13:11 = 5:4
c) 30:45 = 13:24
d) 3:5 = 2:5



Answer
Solution
Correct Answer Is : 12:9 = 16:12
Solution Is : (12/9)=(16/12)
⇒12*12=9*16
⇒ 144=144
Three numbers are in the ratio 1 : 2 : 3 and their HCF is 12. The numbers are

a) 12, 24, 36
b) 5, 10, 15
c) 4, 8, 12
d) 10, 20, 30



Answer
Solution
Correct Answer Is : 12, 24, 36
Solution Is : we know that the H.C.F. of two or more algebraical expression of highest dimensions which divides each of them without remainder. given numbers are in the ratio 1:2:3 let the nos.are 1*x,2*x,3*x so we can write, x=12 (here `x` is the highest dimension and divides the nos without remainder) So the nos. are, 1*12,2*12,3*12 i.e. 12,24,36
PREVIOUS

Preparation for Exams

script type="text/javascript">