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  • SBI SO Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Boats And Streams for SBI SO Exam student. This free online Quantitative Aptitude study material for SBI SO Exam will help students in learning and doing practice on Boats And Streams topic of SBI SO Exam Quantitative Aptitude . The study material on Boats And Streams, help SBI SO Exam Quantitative Aptitude students to learn every aspect of Boats And Streams and prepare themselves for exams by doing online test exercise for Boats And Streams, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SBI SO Exam Quantitative Aptitude Boats And Streams exercise prepared by the highly professionals team. Students can understand Boats And Streams concept easily and consolidate their learning by doing practice test on Boats And Streams regularly till they excel in Quantitative Aptitude Boats And Streams.


Boats And Streams
A boat takes half time in moving a certain distance downstream than upstream. What is ratio between rate in still water and rate of current

a) 1:2
b) 3:1
c) 2:1
d) 1:3



Answer
Solution
Correct Answer Is : 3:1
Solution Is : Let the speed in shill water=X Speed in current=Y upstream speed=X-Y downstream speed =X+Y GIVEN (1/2)(X+Y)=X+Y X+Y=2X-2Y X=3Y X:Y=3:1
The speed of a boat in still water is 6 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 22.5 km and comes back to the starting point. The total time taken by him is :

a) 10 hours
b) 4 hours 10 minutes
c) 6 hours 10 minutes
d) 8 hours



Answer
Solution
Correct Answer Is : 8 hours
Solution Is : Rate downstream = (6+1.5)kmph=7.5 kmph
Rate upstream = (6-1.5)kmph = 4.5kmph
According to the question,
Time = Distance/speed
Therefore, Required time
=(22.5/7.5)+(22.5/4.5)
=3+5
=8 hours.
A boat can travel with a speed of 13 km/hr in still water. If the speed of stream is 4 km/hr in the same direction, time taken by boat to go 63 km in opposite direction is

a) 9hrs
b) 4hrs
c) 7hrs
d) 3 9/17 hrs



Answer
Solution
Correct Answer Is : 7hrs
Solution Is : Rate upstream of boat = 13-4 = 9 kmph.
Therefore required time =Distance / speed. =63/9 = 7hours.
A boat goes 24 km upstream and 28 km downstream in 6 hours. It goes 30 km upstream and 21 km downstream in 6 hours and 30 minutes. The speed of the boat in still water is

a) 8 km/hr
b) 9 km/hr
c) 12 km/hr
d) 10 km/hr



Answer
Solution
Correct Answer Is : 10 km/hr
Solution Is : 24/(x-y) + 28/(x+y) = 6
30/(x-y) + 21/(x+y) = 6.5
Taking 1/(x-y) as X and 1/(x+y) as Y
24X + 28Y = 6
30X + 21Y = 6.5
solving for X and Y=⇒
X = 1/6 and Y = 1/14
so x-y = 6 and x+y = 14 hence
x = 10 kmph and y = 4kmph
A man can row 6 km/h in still water. If the speed of the current is 2 km/h, it takes 3 hours more in upstream than in the downstream for the same distance.The distance is

a) 30 km
b) 24 km
c) 20 km
d) 32 km



Answer
Solution
Correct Answer Is : 24 km
Solution Is : (2) Let the required distance be X km. X _ X = 3 6 - 2 6 + 2 X/4 - X/8 = 3 (2X - X) /8 = 3 X = 3 x 8 = 24 km.
A boat takes half time in moving a certain distance downstream than upstream. What is ratio between rate in still water and rate of current

a) 1:2
b) 3:1
c) 2:1
d) 1:3



Answer
Solution
Correct Answer Is : 3:1
Solution Is : Let the speed in shill water=X Speed in current=Y upstream speed=X-Y downstream speed =X+Y GIVEN (1/2)(X+Y)=X+Y X+Y=2X-2Y X=3Y X:Y=3:1
The speed of a boat in still water is 6 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 22.5 km and comes back to the starting point. The total time taken by him is :

a) 10 hours
b) 4 hours 10 minutes
c) 6 hours 10 minutes
d) 8 hours



Answer
Solution
Correct Answer Is : 8 hours
Solution Is : Rate downstream = (6+1.5)kmph=7.5 kmph
Rate upstream = (6-1.5)kmph = 4.5kmph
According to the question,
Time = Distance/speed
Therefore, Required time
=(22.5/7.5)+(22.5/4.5)
=3+5
=8 hours.
A boat can travel with a speed of 13 km/hr in still water. If the speed of stream is 4 km/hr in the same direction, time taken by boat to go 63 km in opposite direction is

a) 9hrs
b) 4hrs
c) 7hrs
d) 3 9/17 hrs



Answer
Solution
Correct Answer Is : 7hrs
Solution Is : Rate upstream of boat = 13-4 = 9 kmph.
Therefore required time =Distance / speed. =63/9 = 7hours.
A boat goes 24 km upstream and 28 km downstream in 6 hours. It goes 30 km upstream and 21 km downstream in 6 hours and 30 minutes. The speed of the boat in still water is

a) 8 km/hr
b) 9 km/hr
c) 12 km/hr
d) 10 km/hr



Answer
Solution
Correct Answer Is : 10 km/hr
Solution Is : 24/(x-y) + 28/(x+y) = 6
30/(x-y) + 21/(x+y) = 6.5
Taking 1/(x-y) as X and 1/(x+y) as Y
24X + 28Y = 6
30X + 21Y = 6.5
solving for X and Y=⇒
X = 1/6 and Y = 1/14
so x-y = 6 and x+y = 14 hence
x = 10 kmph and y = 4kmph
A man can row 6 km/h in still water. If the speed of the current is 2 km/h, it takes 3 hours more in upstream than in the downstream for the same distance.The distance is

a) 30 km
b) 24 km
c) 20 km
d) 32 km



Answer
Solution
Correct Answer Is : 24 km
Solution Is : (2) Let the required distance be X km. X _ X = 3 6 - 2 6 + 2 X/4 - X/8 = 3 (2X - X) /8 = 3 X = 3 x 8 = 24 km.
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