#### IBPS PO CWE Exam Quantitative Aptitude Study Material

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b) Y-x

c) Xy/x-y

d) Xy/y-x

work done by B in one hour=1/y

Both A and B together work in one hour=(1/x)-(1/y) =(y-x)/xy.

Both A and B fill tank in xy/(y-x) hours.

b) 14 minutes

c) 15 minutes

d) 30 minutes

work done by 2nd tap in one minute =1/45

Both taps one minute work =(1/30)+(1/45)

=(45+30)/1350

=75/1350 =1/18.

Both tap will empty the tank in 18 minutes.

b) 71 ml

c) 52 ml

d) 81 ml

Quantity of water =(2/9)*729 =162ml

Let `x` be the quantity that should be added to make the ratio 7:3.

According to the question, 567/(162+x) =7/3

=>1701 =1134+7x

=> 7x =1701 -1134

=>x=81ml

b) Rs. 525

c) Rs. 485

d) Rs. 450

b) 3 1/2

c) 3 1/4

d) 4 2/3

b) 13 : 22

c) 14 : 25

d) 12 : 23

4kg of second alloy could be mixed together.

Therefore, In 3kg of mixture,

Tin = 1kg

Iron = 2kg.

In 4kg of mixture,

Tin=(2/5)×4 = 8/5 kg=1.6kg

Iron=(3/5)×4=12/5=2.4kg

Therefore,Required ratio

=(1+1.6) : (2+2.4) =2.6 : 4.4

13 : 22

b) 12

c) 36

d) 24

b) 5 hours 30 minutes

c) 5 hours 20 minutes

d) 4 hours 48 minutes

b) 8000 l

c) 6000 l

d) 4000 l

b) 2 : 1

c) 2 : 3

d) 3 : 2

Two mean proportionals

= 2r & 2r2 = 2(3), 2(3)2

= 6, 18.