#### UIIC ASSISTANT RECRUITMENT Numerical Ability Study Material

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b) 12 yr

c) 10 yr

d) 8 yr

b) 40 years

c) 36 years

d) 54 years

b) 11yr

c) 10.5yr

d) 11.5yr

b) 34 yr

c) 28 yr

d) 32 yr

b) 10yr

c) 37yr

d) 39yr

b) 19 years

c) 29 years

d) 38 years

b) 5:2

c) 11:7

d) 13:9

Father`s age = 7x , son`s age = 3x

Now , from given condition

7x *3x = 756 ---> 21x2 = 756

x2 = 756/21 = 36 ---> x = √36 = 6

Father`s age = 7x6 = 42 yr

Son`s age = 3x6 = 18 yr

After 6 years

Father`s age = 42 + 6 = 48 yr

Son`s age = 18 + 6 = 24 yr

Required ratio = 48/24 = 2/1 = 2:1

b) 45

c) 40

d) 60

Number of men = 100 - x

Then , by given condition ,

28x + 45 ( 100 - x ) = 100 x 365

28 x + 4500 - 45x = 3650

17x = 850 = x = 850/17 = 50

Number of women = 50

b) 36

c) 40

d) 48

b) 40 yr

c) 50 yr

d) 45 yr

=27*3+3*3=90yr

Present age of (wife+child)=20*2+2*5=50 yr

Precent age of husband =(90-50)=40yr