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  • SSC CGL Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Time And Distance for SSC CGL Exam student. This free online Quantitative Aptitude study material for SSC CGL Exam will help students in learning and doing practice on Time And Distance topic of SSC CGL Exam Quantitative Aptitude. The study material on Time And Distance, help SSC CGL Exam Quantitative Aptitude students to learn every aspect of Time And Distance and prepare themselves for exams by doing online test exercise for Time And Distance, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SSC CGL Exam Quantitative Aptitude Time And Distance exercise prepared by the highly professionals team. Students can understand Time And Distance concept easily and consolidate their learning by doing practice test on Time And Distance regularly till they excel in Quantitative Aptitude Time And Distance.


Time And Distance
A bus moving at 40km per hour covers a distance in 6 hours 15 minutes. If it travels the same distance at 50 km per hour how long will it take to cover the distance ?

a) 2 hrs
b) 6 hrs
c) 4 hrs
d) 5 hrs



Answer
Solution
Correct Answer Is : 5 hrs
Solution Is : Distance = speed x Time = ( 40x6 1/4 ) km = ( 40 x 25 /4 ) km = 250 km New speed = 50 kmph Required time = Distance / Speed = 250 / 50 = 5 hours
2 km 5 m is equal to

a) 2.05 km
b) 2.5 km
c) 2.005 km
d) 2.0005 km



Answer
Solution
Correct Answer Is : 2.005 km
Solution Is : 1000 metre = 1 km 5 metre = 5 / 1000 = 0.005 km = 2km 2 metre = (2 + 0.005) km = 2.005 km
A student goes to school at the rate of 5/2 km/hr and reaches 6 minutes late. If he travels at the speed of 3 km/hr, he reaches 10 minutes earlier. The distance of the school is

a) 45 Km
b) 20 Km
c) 10 Km
d) 4 Km



Answer
Solution
Correct Answer Is : 4 Km
Solution Is : Distance o school = x km Difference of time = 16 minutes = 16/60 hour x/5/2 - x/3 = 16/60 2x/5 - x/3 = 4/15 6x-5x/15 = 4/15 x/15 = 4/15 x = 4/15 * 15 = 4 km
Motor-cyclist P started his journey at a speed of 30 km/hr. After 30 minutes, motor-cyclist Q started from the same place with a speed of 40 km/hr. How much time ( in hours) will Q take to over-take P ?

a) 1
b) 1 1/2
c) 3/8
d) 2



Answer
Solution
Correct Answer Is : 1 1/2
Solution Is : (2) Distance covered by motor-cyclist P in 30 minutes = 30*1/2 = 15 km Relative Speed =40-30=10 kmph Therefore, Required speed =Time taken to cover is km at 10 kmph =15/10 =3/2 hours
In a 500 meter race , the ratio of speed of two runners P and Q is 3:5. P has a start of 200 meter then the distance between P and Q at the finish of the race is

a) P wins by 100meter
b) Both reach at the same time
c) Q wins by 100 meter
d) Q wins by 50 meter



Answer
Solution
Correct Answer Is : Both reach at the same time
Solution Is : Time taken by P in covering 300 meter =(300/3) =100 second Distance covered by Q in 100 second =5*100 =500meter
A man swim at 5 km per hour velocity in still water. He takes 75 minutes to swim from position A to the position B and back in a river when it is flowing at 1 km per hour. The distance between A and B is

a) 6 km
b) 5 km
c) 2.5 km
d) 3 km



Answer
Solution
Correct Answer Is : 3 km
Solution Is : Rate downstream = 5 + 1 = 6 kmph Rate upstream = 5 -1 = 4 kmph If AB = X km, then X/6 + X/4 = 75/60 => 2X + 3X/12 = 5/4 => X/12 = 1/4 => X = 3 km
A trader told his servant Shambhu that he left for his home from the shop after every 2:40 hours. I left for home 55 minutes earlier and for the next time I will leave for home from my shop at 8:5 p.m. At which time did I inform my servant?

a) 6:30
b) 6:00
c) 6:15
d) 4:20



Answer
Solution
Correct Answer Is : 6:30
Solution Is : The trader Left for his home from the shop for every 2.40 hour. Given, for the next time he will leave for home is 8:15 pm. Hence the previous time he left for home is 8:15 p.m. - 2.40 hrs. =5.35pm Hence the time at which he informed his servant is =5.35 pm + 55 mins =6.30 p.m
Nivedita stops to walk after covering a distance of 10 km to the west. She then turns to the right and walks 8km. Again she walks 4 km to the right. How far is she from her office?

a) 18 km
b) 8 km
c) 16 km
d) 10 km



Answer
Solution
Correct Answer Is : 10 km
Solution Is :
Raj and Prem walk in opposite directions at the rate of 3 km and 2 km per hour respectively. How far will they be from each other after 2 hours ?

a) 10 Km
b) 8Km
c) 6Km
d) 2Km



Answer
Solution
Correct Answer Is : 10 Km
Solution Is : Relative speed = 3+2 - 5Kmph.
Therefore Required distance = speed* Time =5*2 =10Km
A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. The distance (in metres) between them after 6 minutes is

a) 190
b) 200
c) 100
d) 150



Answer
Solution
Correct Answer Is : 100
Solution Is : Relative Speed = 11-10 = 1Kmph
Distance covered in 6 minutes=(1000/60)*6 metre =100 metre
Therefore Remaining distance =200-100 =100metre.
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