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  • RRB NTPC Exam Last Year Paper RRB NTPC 2013 Asm Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Last Year Paper RRB NTPC 2013 Asm ASM Oct 13 paper for RRB NTPC Exam student. This free online Last Year Paper RRB NTPC 2013 Asm study material for RRB NTPC Exam will help students in learning and doing practice on ASM Oct 13 paper topic of RRB NTPC Exam Last Year Paper RRB NTPC 2013 Asm . The study material on ASM Oct 13 paper, help RRB NTPC Exam Last Year Paper RRB NTPC 2013 Asm students to learn every aspect of ASM Oct 13 paper and prepare themselves for exams by doing online test exercise for ASM Oct 13 paper, as their study progresses in class. Kidsfront provide unique pattern of learning Last Year Paper RRB NTPC 2013 Asm with free online comprehensive study material and loads of RRB NTPC Exam Last Year Paper RRB NTPC 2013 Asm ASM Oct 13 paper exercise prepared by the highly professionals team. Students can understand ASM Oct 13 paper concept easily and consolidate their learning by doing practice test on ASM Oct 13 paper regularly till they excel in Last Year Paper RRB NTPC 2013 Asm ASM Oct 13 paper.


ASM Oct 13 paper
REASONING

22 boys are standing in front of Kunal in a queue, 12 boys are standing to the back of Rohit in the same queue. If total number of boys is 30 then the number of boys is 30 then the number of boys standing in between Kunal and Rohit is

a) 3
b) 4
c) 6
d) 5


✔Answer
✔Solution
Correct Answer Is : 4
Solution Is :
REASONING

In the following sequence of alphabets aababaababaaabbababbaaaa the number of a`s from left and 7th `a` from rights is

a) 1
b) 0
c) 3
d) 2


✔Answer
✔Solution
Correct Answer Is : 1
Solution Is :
REASONING

If A stands for `+`. B stands for `-`, C stands for `X` and D for `÷` then 1/2A 1/3B 1/4C 1/5D 1/6 =

a) 0
b) 17/30
c) 8/15
d) 13/15


✔Answer
✔Solution
Correct Answer Is : 8/15
Solution Is :
REASONING

If 1st July, 1977 was a Friday then 1st July 1970 was a

a) Wednesday
b) Thursday
c) Sunday
d) Tuesday


✔Answer
✔Solution
Correct Answer Is : Wednesday
Solution Is : Number of odd days up to 1st July 1977 = 3 Number of odd days in January 1977 = 3 Number of odd days in February 1977 = 0 Number of odd days in March 1977 = 3 Number of odd days in April 1977 = 2 Number of odd days in May 1977 = 3 Number of odd days in June 1977 = 2 Total number of odd days = 13 odd days In 1976 was a leap year, so number of odd days = 2 In 1975 number of odd day = 1 In 1974 number of odd day = 1 In 1973 number of odd day = 1 In 1972 was a leap year, so number of odd days = 2 In 1971, number of odd day = 1 Total number of odd days = 8 odd days Number of odd days in 1970 from December to 1st July = 3 + 2 + 3 + 2 + 3 + 3 = 16 Total number of odd days = 13 + 8 + 16 = 37. i.e. 2 odd days Therefore, 1st July, 1970 was two days before Friday, i.e., Wednesday
REASONING

If `A + B` stands for `A is the father of B` , `A - B` stands for `A is the brother of B`, `A X B` stands for `A is the wife of B` and `A ÷ B` stands for `A is the sister of B` then `P + Q ÷ R` means

a) P may be father of R
b) R is sister of P
c) R may be father of P
d) R is sister of Q


✔Answer
✔Solution
Correct Answer Is : P may be father of R
Solution Is : P + Q → P is father of Q. Q ÷ R → Q is the sister of R. There fore, P is the father of Q and R.
REASONING

In a certain code language `278` means `run very fast`. `853` means `come back fast` and `376` means `run and come` then `back` may be represented by the digit

a) 3
b) 7
c) 5
d) 6


✔Answer
✔Solution
Correct Answer Is : 5
Solution Is :
REASONING

If X is player then X must be stout. This statement can be deduced from

a) Only players are stout
b) None but the stout men are players
c) All stout men are players
d) Some players are stout


✔Answer
✔Solution
Correct Answer Is : Some players are stout
Solution Is : The statement implies that all players are stout. If all players are stout, them some players must be stout.
REASONING

Find the odd one out.

a) Kitchen
b) Psychology
c) Campaign
d) Utensil


✔Answer
✔Solution
Correct Answer Is : Campaign
Solution Is : Campaign is used as both Verb and Noun. All other words are Nouns.
REASONING

Natural : Artificial : : Spontaneous : ?

a) Calculated
b) Impromptu
c) Instinctive
d) Free of all


✔Answer
✔Solution
Correct Answer Is : Calculated
Solution Is : Natural is the antonym of Artificial. Similarly, Spontaneous is the antonym of Calculated.
QUANTITATIVE APTITUDE

The sum of all the natural numbers between 301 and 501 (including 301 and 501) which are divisible by 7 is

a) 11277
b) 12571
c) 15171
d) 11571


✔Answer
✔Solution
Correct Answer Is : 11571
Solution Is : The smallest number = 301 The largest number = 497 common difference = d = 7 tn = a + (n-1) d =? 497 = 301 + (n-1) X 7 =? (n-1) X 7 = 497 - 301 = 196 =? n-1 = 196 ÷ 7 = 28 =? n = 28 + 1 = 29 Required sum = n/2 ( first term + last term ) 29/2 ( 301 + 497 ) 29 X 798/2 = 11571

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