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  • UIIC ASSISTANT RECRUITMENT Numerical Ability Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Numerical Ability Simple And Compound Interest for UIIC ASSISTANT RECRUITMENT student. This free online Numerical Ability study material for UIIC ASSISTANT RECRUITMENT will help students in learning and doing practice on Simple And Compound Interest topic of UIIC ASSISTANT RECRUITMENT Numerical Ability. The study material on Simple And Compound Interest, help UIIC ASSISTANT RECRUITMENT Numerical Ability students to learn every aspect of Simple And Compound Interest and prepare themselves for exams by doing online test exercise for Simple And Compound Interest, as their study progresses in class. Kidsfront provide unique pattern of learning Numerical Ability with free online comprehensive study material and loads of UIIC ASSISTANT RECRUITMENT Numerical Ability Simple And Compound Interest exercise prepared by the highly professionals team. Students can understand Simple And Compound Interest concept easily and consolidate their learning by doing practice test on Simple And Compound Interest regularly till they excel in Numerical Ability Simple And Compound Interest.


Simple And Compound Interest
Find the difference between Simple and Compond interest for an amount Rs 1800 lended for 2 years at 10 % per annum . ( in rs)

a) 15
b) 150
c) 18
d) 20



Answer
Solution
Correct Answer Is : 18
Solution Is : Simple interest = PNR / 100 = 1800*2*10 / 100 = Rs. 360 Compound interest = P ( 1 +r/100)n - P = 1800 ( 1 + 10/100)2 - 1800 = 1800 * 110 * 110 / 100*100 - 1800 = Rs 378 Required difference = 378 - 360 = Rs . 18
In how many years shall Rs 5000, invested at the rate of 4 % simple interest per annum , amount to Rs 6600 ?

a) 10
b) 8
c) 6
d) 8.5



Answer
Solution
Correct Answer Is : 8
Solution Is : P = 5000 R = 4 % A = 6600 SI = A - P = 6600 - 5000 SI = 1600 N = ? SI = PNR / 100 1600 = 5000xNx4/100 N = 1600 x 100 / 4x5000 N = 160000/20000 N = 16/2 = 8 yr
A sum is invested for 3 years at a certain rate of interest compounded annually. After 3 yeatrs the amount increases by 119.7 % . What is the rate of interest ?

a) 20
b) 10
c) 15
d) 30



Answer
Solution
Correct Answer Is : 30
Solution Is : Suppose initial amount be 1000 The amount increases by 119.7 % Hence , final amount = 1000 + 1197 = 2197 Rate of interest r% , then 1000(1 + r/100)3 = 2197 --> (1 + r/100)3 = (13/10 )3 r = 30 %
A sum of money doubles itself in 10 years at simple interest . In how many years would it become 5 times of itself ?

a) 30
b) 45
c) 40
d) 50



Answer
Solution
Correct Answer Is : 40
Solution Is : SI in first case = A - P = 2P - P = P SI = PxRxT / 100 P = P xR 10 / 100 r = 100P / 10 P = 10 % Similarly S.I in II case = 5P -P = 4P T = 4PX100 / PX10 = 40 years
A man buys land and pays 20 times its annual rent. What is the rate % ?

a) 6 %
b) 0.05
c) 0.1
d) 0.08



Answer
Solution
Correct Answer Is : 0.05
Solution Is : Annual rent can be treated as simple interest and price for which land is bought should be treated as principle amount hence SI = k and P = 20 k , SI = PNR / 100 k = 20kxRx1/100 R = 100 k / 20 k = 5 %
At what rate percent compound interest does a sum becomes nine-fold in 2 years ?

a) 150 %
b) 1
c) 2
d) 4



Answer
Solution
Correct Answer Is : 2
Solution Is : Let sum be Rs . P , then , 9P = P ( 1 + r/100) 2 1 + r/100 = 3 r = 200 %
The difference between the compound interest and simple interest on a certain sum for 2 yr at 6% per annum is Rs 27. The sum is

a) Rs 5000
b) Rs 550
c) Rs 7000
d) Rs 7500



Answer
Solution
Correct Answer Is : Rs 7500
Solution Is :
The compound interest on Rs 1800 at 10 % per annum , for a certain period od time is Rs 378 . Find the time in years

a) 1.5
b) 2.5
c) 2
d) 3



Answer
Solution
Correct Answer Is : 2
Solution Is :
In how many years shall Rs 2500, invested at the rate of 8 % simple interest per annum , amount to Rs 3300 ?

a) 5
b) 4
c) 6
d) 4 1/2



Answer
Solution
Correct Answer Is : 4
Solution Is : P = 2500
R = 8 %
A = 3300
SI = A - P = 3300 - 2500
SI = 800
N = ?
SI = PNR / 100
800 = 2500xNx8/100
N = 800 x 100 / 8x2500
N = 10000/2500
N = 100/25 = 4 yr
A person invests RS 12000 as fixed deposit at a bank at the rate of 10% per annum simple interest. But due to some pressing needs he has to withdraw the entire money after 3yr, for which the bank allowed him a lower rate of interest. If he gets Rs 3320 less than what he would have got at the end of 5yr, the rate of interest allowed by the bank is

a)
b)
c)
d)



Answer
Solution
Correct Answer Is :
Solution Is :
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